In a 5-inch type tube, what is the result of a reduction of 5 inches to 1 inch?

When discussing the reduction in a 5-inch type tube to a 1-inch type tube, what’s essential to note is that this involves understanding the relationship between the dimensions or size of the tube and its corresponding volume or capacity.

In this context, when you reduce the diameter of a tube from 5 inches to 1 inch, you are effectively reducing the cross-sectional area of the tube. The cross-sectional area of a circular tube can be calculated using the formula ( A = \pi r^2 ), where ( r ) is the radius.

For the 5-inch tube:

• The radius is 2.5 inches (half of 5 inches), so the area is ( A_1 = \pi (2.5)^2 = 6.25\pi ).

For the 1-inch tube:

• The radius is 0.5 inches, leading to an area of ( A_2 = \pi (0.5)^2 = 0.25\pi ).

To find how many times the area of the 5-inch tube is greater than the area of the 1-inch tube, divide the area of the larger tube by the area of the smaller one:

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